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Hiperbola(2)

Bentuk umum persamaan hiperbola adalah dengan A. hiperbola didefinisikan sebagai ... 0) • Pusat O (0. panjang sumbu minor = 2b Persamaan asimtot: y = .

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KELOMPOK 2 KELOMPOK IRISAN KERUCUT HIPERBOLA Alfra Putriana D / 03 Arjun Duan P / 0!  "#natan Mar$%llin Mar$%llin# #M/ &' Ri()a Nurlaill* / 32 P%r(a)aan Hi,%r-#la .i ,u(at P , 1 P%n+%rtia n Hi,%r-#la ari( Sin++un+ Hi,%r-#la P%r(a)aan Hi,%r-#la .i ,u(at O 0 01 B%ntu4 U)u) P%r(a)aa n Hi,%r-#la P%n+%rtian Hi,%r-#la • • • • • Hiperbola )%ru,a4an 4ur5a l%n+4un+ t%r-u4a *an+ t%r.iri ata( .ua -a+ian atau $a-an+ *an+ (alin+ (i)%tri( t%ra.a, .ua (u)-u (i)%tri6 Hiperbola .i,%r#l% .%n+an )%n+iri( .ua -an+un 4%ru$ut *an+ (alin+ -%rt#la4 -%la4an+ (%(uai -i.an+ *an+ t%+a4 luru( ala( 4%ru$ut t%ta,i ti.a4 )%)#t#n+ ,un$a4 4%ru$ut6 Dala) -i.an+ 4##r.inat hiperbola .i.%fni(i4an (%-a+ai t%),at 4%.u.u4an titi47titi4 *an+ (%li(i jara4n*a t%ra.a, .ua titi4 t%rt%ntu (%lalu t%ta,6 K%.ua titi4 t%rt%ntu itu .ina)a4an titik fokus. B%ntu4 u)u) ,%r(a)aan i,%r-#la a.ala .%n+an A B C D E -ilan+an r%al .an A B 8 06 Un(ur Hi,%r-#la Keterangan:  Titi4 O .i(%-ut ,u(at i,%r-#la6  Titi4 .an .i(%-ut ;#4u( i,%r-#la6 Titi4 .an .i(%-ut titi4 ,un$a4 i,%r-#la6  Rua( +ari( .i(%-ut (u)-u )a*#r/(u)-u ,anjan+ .an )%)ili4i ,anjan+ *an+ .in*ata4an .%n+an 2a. Rua( +ari( .i(%-ut (u)-u i)ajin%r/ (u)-u )in#r .an )%)ili4i ,anjan+ *an+ .in*ata4an .%n+an 2b6 Su)-u (i)%tri *an+ )%lalui 4%.ua ;#4u( .i(%-ut (u)-u uta)a atau (u)-u tran(5%r(al6 Su)-u (i)%tri *an+ )%lalui titi4 ,u(at .an t%+a4 luru( (u)-u uta)a .i(%-ut (u)-u (%4a P%r(a)aan i,%r-#la ? Pu(at i,%r-#la O 0 01 @#4u( i,%r-#la @&7$ 01 .an @2$ 01 .%n+an $2=a2-2 Pun$a4 i,%r-#la A&7a 01 .an A2a 01 Su)-u n*ata a.ala * = 0 (u)-u i)ajin%r a.ala  = 0 Panjan+ (u)-u )a*#r = 2a ,anjan+ (u)-u )in#r = 2P%r(a)aan a(i)t#t? * =       P%)-u4tian ,a.a ,u(,%r(a)aan i,%r-#la at O 0 01 (u)-u uta)a (u)-u,a.a  i,%r-#la (%in++a -%rla4u ,%r(a)aan  Titi4(%jajar P  *1 t%rl%ta4 P@:  P@ = 2a666666&1 D%n+an )%n++una4an ru)u( untu4 )%n$ari jara4 antara 2 titi4 .i,%r#l% P@:= .an P@= A4i-atn*a ,%r(a)aan &1 )%nja.i D%n+an )%n+4ua.rat4an 4%.ua rua( .i,%r#l% $ 7 a2 = D%n+an )%)-a+i 4%.ua rua( .%n+an -ilan+an  .i,%r#l% $ 7 a2 = a S%lanjutn*a 4%.ua rua( .i4ua.rat4an .an .i,%r#l% a  $22 7 2a2$ = a 2 7 $1 2  *2F a  $22 7 2a2$ = a  $22 7 2a2$ = a a2$2 = a22 7 $22  a2*2 K%.ua rua( .i-a+i .%n+an -ilan+an 7& (%in++a .i,%r#l% a2$2 7 a21 = $2 7 a212 7 a2*2 K%.ua rua( .i-a+i .%n+an a 2$2 7 a21 .i,%r#l%  & =  T%la .ij%la(4an (%-%lu)n*a -a P%r(a)aan i,%r-#la ? Pu(at i,%r-#la .i , 1  Titi4 ;#4u( , 7 $ 1 .an ,  $ 1 .%n+an =   Titi4 ,un$a4 , 7 a 1 .an ,  a 1 Su)-u n*ata a.ala * =  .an (u)-u i)ajin%r a.ala  = , P%r(a)aan a(i)t#t ? *   =   ,1      • Pu(at P , 1 Su)-u Uta)a S%jajar Su)-u G P%r(a)aan i,%r-#la ? Pu(at i,%r-#la .i , 1  Titi4 ;#4u( ,   $1 .an ,   $1 .%n+an =   Titi4 ,un$a4 ,   a1 .an ,   a1 Su)-u n*ata a.ala  = , .an (u)-u i)ajin%r a.ala * =  P%r(a)aan a(i)t#t ? *   =   ,1      #  C#nt# S#al .an P%)-aa(an &6 S%-ua i,%r-#la )%),un*ai ,%r(a)aan ' 2  *2  3!  *  ! = 06  T%ntu4an titi4 ,u(at titi4 ,un$a4 .an titi4 ;#4u( i,%r-#la t%r(%-ut Pembahasan '2  *2  3!  *  ! = 0 '2  3!  *2  * = ! '2  1  *2  2*1 = ! '2    1  *2  2*  &1 = !  3!   ? & '  212  *  &12 = 3! *  &12  '  212 = 3! 7 =& P%r(a)aan i,%r-#la ini )%)ili4i (u)-u uta)a *an+ (%jajar .%n+an (u)-u *6 Ma4a • S%in++a ?  Titi4 ,u(at ,1 = 2 7&1  Titi4 ,un$a4 ,   a1 = 2 7&1  31 = 2 21  Titi4 ,un$a4 ,  7 a1 = 2 7&1  31 = 2 71  Titi4 ;#4u( ,   $1 = 2 7&1 1  Titi4 ;#4u( ,  7 $1 =  2 7&1 7 1      26 T%ntu4an ,%r(a)aan i,%r-#la *an+ ;#4u(n*a .i J21 .an 4##r.inat 4%.ua ,un$a4n*a a.ala 72 21 .an ! 21  Pembahasan • )i(al ,u(atn*a , 1 ,un$a4n*a 72 21 .an ! 21 )a4a  = 2 .an (u)-u n*ata (%jajar (u)-u > *aitu * = 2 ,a=! ,  a = 72  2, =  , = 2 titi4 ,u(at 2 21 P=2 ,a ,$=J =! 2$=J 2a $= = != 7 = 7 = 2  &! = ' Ma4a  a =  S%in++a ,%r(a)aan i,%r-#lan*a a.ala ? B%ntu4 u)u) ,%r(a)aan i,%r-#la • • B%ntu4 u)u) ,%r(a)aan i,%r-#la a.ala .%n+an A B C D E -ilan+an r%al .an A B 8 06 C#nt# S#al .an P%)-aa(an &6 T%ntu4an 4##r.inat titi4 ,un$a4titi4 ;#4u(titi4 ,u(at.an ,%r(a)aan a(i)t#t .ari i,%r-#la .%n+an ,%r(a)aan -%ri4ut6 '2 7 &!*2 7 & 7 !* 7 &'' = 0 Pembahasan : '2 7 &!*2 7 & 7 !*  &'' = 0 '2 7 &!*2 7 & 7 !* = &'' '2 7 21 7 &!*2  *1 = &'' '2 7 2  &1 7 &!*2  *  1 = &'' ' 7 &12 7 &!*  212 = &''  ' 7 ! 26 D%n+an ,%r(a)aan i,%r-#la 27*2707 2*'t%ntu4an A6 K##r.inat titi4 ,u(at B6 K##r.inat titi4 ;#4u( C6 K##r.inat titi4 ,un$a4 D6 P%r(a)aan A(i)t#t Pembahasan : 2 7 *2 7 0 7 2*  ' = 0 2 7 *2 7 0 7 2* = 7' 2 7 &0  21 7 *2  2*  &1 = 7'  &00 7 & ? 2 2  7 1 7 *  &1 =   7 12 7 = & A2 = & B2 =  A=& B=2 C= S%in++a ? A6 K##r.inat Titi4 ,u(at 7&1 B6 K##r.inat Titi4 @#4u( 77&1 .an 7&1 C6 K .inat Titi4 P 4 7&1 .an ari( Sin++un+ Hi,%r-#la a6 ari( Sin++un+ .i Suatu Titi4 ,a.a Hi,%r-#la •  ,%r(a)aan +ari( (in++un+ .i P 1 ,a.a i,%r-#la ? &1 a.ala 21 a.ala 31 a.ala 1 a.ala -6 ari( Sin++un+ Hi,%r-#la .ari Suatu Titi4 .i Luar Hi,%r-#la • Seperti pada parabola untuk menentukan persamaan garis singgung di titik P () di luar hiperbola dapat dilakukan dengan menentukan lebih dahulu garis polar (garis kutub).  G P    Mi(al P 1 .i luar i,%r-#la 6 P .an PR a.ala +ari( (in++un+ .%n+an titi4 (in++un+  .an R6 ari( R a.ala +ari( ,#lar +ari( 4utu-1 titi4 P6 Ma4a ,%r(a)ann*a ? $6 ari( Sin++un+ Hi,%r-#la .%n+an ra.i%n T%rt%ntu P%r(a)aan +ari( (in++un+ .%n+an +ra.i%n ) ,a.a i,%r-#la ? &1 21 31 1 = & a.ala * = ) = & a.ala * = ) a.ala *   = )  ,1 = & a.ala *   = )  ,1 C#nt# S#al .an P%)-aa(an &6 T%ntu4an ,%r(a)aan +ari( (in++un+ i,%r-#la .i titi4 ! 21 • • Pembahasan  Titi4 ! 21 t%rl%ta4 ,a.a i,%r-#la6 P%r(a)aan +ari( (in++un+ .i titi4 ! 21 a.ala ? &*&=2 *= 26 T%ntu4an ,%r(a)aan +ari( (in++un+ i,%r-#la = & *an+ (%jajar +ari( * = 2  & • Pembahasan = & )a4a * = 2  & ) = 2 )a4a +ra.i%n +ari( (in++un+ = 2 P%r(a)aan +ari( (in++un+ a.ala? * = 2 * = 2 * = 2 •  T%ri)a 4a(i 