Transcript
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID)
1)
ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e
Weight of component to be lifted
=
Component force acting on beam, F
=
Impact factor
=
SKID LUG SIING
*istance from lug hole to edge of beam,
=
Lug radius, 'L
=
Lug thickness, !L thickness, !L
=
Lug base width, /L
=
*iameter of hole, *
=
*istance from lug hole to base, L
=
Collar plate thickness, !
=
Collar ring diameter, D
= Clearance btw shackle & lug size
A =
C=
!"#
Lug thickness, tL mm
$
m
#%"%
Lug radius, rL mm
$
m
'ince A & C clearance clearance against against Lug size , (herefore (herefore the Lu ACCEPTABLE
Per PTS Section 6.3 a) Lug hole diameter, * shall be M2 #3
i) *p + mm
=
ii) *p - ."
%$=
b) Lug hole diameter, * shall be e$$ !n 4 (D 5 6&&) *p =
= result
a) =
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e b) = /ole,d
*iameter of hole, d
btw
."$
"$
0o of lug e1e,
=
2a3imum combined force acting on lug e1e, Fc
= =
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID)
7)
ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e
LIFTI LIFTING NG LUG LUG MA MATERI TERIAL AL MEC9 MEC9AN ANIC ICAL AL PROP PROPER ERTI TIES ES 2aterial used
=
'pecified 1ield stress, '1
=
Allowable bending stress, fb3"all 4 = $"55'1 ) 6In 7lane
=
Allowable bending stress, fb1"all 4 = $"%'1 ) 68ut 8f 7lane
=
Allowable tensile stress, 't"all 4 = $"5'1 )
=
Allowable bearing stress, 'br"all 4 = $"#'1 )
=
Allowable shear stress, 's"all 4 = $"'1 )
=
S9ACKLES 'hackle rating 4 '"W"L )
9
(1pe of shackle
:8L( (1pe An
7in size, *p
=
MAIMUM SLING TENSION ON PADE;E FAC(8< 8F 'AF(>
(s
=
F"8"'"
=
DESIGN LOAD: 'LI0; (0'I80 LIF(I0; A0;L AC(@AL 8@( 8F 7LA0 A0;L
7 = F8' ? (s
P ,
= = =
<(ICAL F8
Fz = 7 ? sin a
F<
=
8@( 8F 7LA0 F8
F3 = 7 ? cos a
F2
=
e2
=
M%
=
M2
=
/orizontal dist"7I0 CL to 0"A"
)
STRESS C9 C9ECK AT =A =ASE ) M#&en! M#&en! C ! ! *"$!ne *"$!ne > 9 In 7lane 2oment
21 = 4 F3?/ ) 4 Fz?e3 l)
8ut of plane moment
23 = 4 F1I?hL )
,) Ten$"e en$"e S!'e$ S!'e$$ $ 2a3imum tensile force, ft = Fz D E tL ? wL
=
Allowable tensile stress, 't"all 4 = $"5'1 )
=
'ince ft
4
't"all, therefore the lug size is
$!"$3!#'%.
) =en*"n? =en*"n? $!'e$$ $!'e$$ (In Pne) Pne) 2a3imum bending stress , fb3 = 4 5?23 ) D 4 wL ? E4tL+tcp)G! )
=
Allowable bending stress, fb3"all 4 = $"55'1 ) 6In 7lane
=
'ince fb3
4
fb3"all,therefore the lug size is
*) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
$!"$3!#'%.
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e
2a3imum bending stress , fb1 = 4 5?21 ) D E tL +4!?tcp) ? E wLG! )
=
Allowable bending stress, fb1"all 4 = $"%'1 ) 68ut 8f 7lane
=
'ince fb1
4
fb1"all,therefore fb1"all,therefore the lug s ize is
$!"$3!#'%.
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e
e) C#&,"ne* C#&,"ne* $!'e$ $!'e$$e$ $e$>> @
=
S!@S!. 5 3,%@3,%. 5 3,2@3,2.
'ince @
H
., therefore the lug size is
= $!"$3!#'%.
3) S9EAR S9EAR $!'e$$ $!'e$$ (In Pne) Pne) 2a3imum '/A< stress , fs3 = F3 D E wL ? tL
=
Allowable shear stress, 's"all 4 = $"'1 )
=
'ince fs3
4
's"all,therefore the lug size is
$!"$3!#'%.
?) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne) 2a3imum '/A< stress , fs1 = F1l D E wL ? tL
=
Allowable shear stress, 's"all 4 = $"'1 )
=
'ince fs3
.1) .1)
4
's"all,therefore the lug size is
$!"$3!#'%.
C9EC C9ECKI KING NG ONON-MI MISE SES S CRI CRITE TERI RIA A ) 'um of stress in -7LA0
32 B S! 5 3,% =
,) 'um of stress in >7LA0
3% B S! 5 3,2 =
) (herefore, aerage 'hear stress
32% B SRT (3$27)5(3$%7) =
*) 2a3imum Combined stress F#&, B SRT (327)5(3%7)-(3253%532%7) = Allowable combined stress 9 Fcomb"all 4 = $"55'1 ) = 'ince fs3
)
4
's"all,therefore the lug size is
$!"$3!#'%.
STRESS C9 C9ECK AT PI PIN 9O 9OLE ) Ten$"e en$"e S!'e$ S!'e$$ $ 2a3imum tensile force, P
=
Cross sectional area of lug e1e, A! B 7 H ( !LH ( 'L - *@7 )) 5 7 H ( !H = (( D@7) - *@7 )) 5 7 H ( !H (( D @7) - *@7 )) (ensile stress, 't
=
Allowable tensile stress, 't"all 4 = $"5'1 )
=
'ince 't
4
't"all, therefore the lug size is
$!"$3!#'%.
,) =e'" =e'"n? n? S!'e$$ S!'e$$ 2a3imum bearing force, P
=
Cross sectional area of lug e1e, A, B D H ( !L 5 7! )
=
:earing stress, 'br = Fbr D Ab
=
Allowable bearing stress, 'br"all 4 = $"#'1 )
=
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e
'ince 'br
4
'br"all,therefore the lug size is
$!"$3!#'%.
LIFTING LUG DESIGN CALCULA CALCU LATION TION (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inj Inje e!" !"#n #n $%$! $%$!e& e& (A-6 (A-6810 810)) - Pe'& Pe'&$ $ F"e F"e* * S+, S+,$! $!'+ '+! !+' +'e e
) Se' Se' S!'e$ S!'e$$ $
J
2a3imum shear force, P force, P
=
Cross sectional area of lug e1e, A! B 7 H ( !LH ( 'L - *@7 )) 5 7 H ( !H (( D@7) - *@7 )) 5 7 H ( !H (( D @7) - *@7 ))
=
'hear stress, 's
=
Allowable shear stress, 's"all 4 = $"'1 )
=
'ince 's
4
's"all,therefore the lug size is
$!"$3!#'%.
*) C#&,"ne* C#&,"ne* $!'e$ $!'e$$e$ $e$>> @
=
S!@S!. 5 3,%@3,%. 5 3,2@3,2.
'ince @
)
H
., therefore the lug size is
= $!"$3!#'%.
ELD SI SIE CA CALCULATIONS Weld leg used,
=
Weld throat thickness used, tr
=
Filler metal material
9
Fillet weld Koint efficienc1, efficienc1, E
=
Welding stress for steel grade ( E- ), ),
=
Allowable welding stress,S/ stress,S/
=
() Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force,Ft
=
Area of weld, A/ B 7H(!L5/L)H!'
=
(ensile stress, 't = E4FtDAw) 'ince 't
4
= 'w,therefore weld leg is
$!"$3!#'%.
(,) Se' Se' $!'e $!'e$$ $$ 2a3imum shear force,Ft
=
'hear stress, S$ B (F!@A/)
=
Allowable welding stress for steel grade 4 ), 'w
=
'ince 's
H
'w,therefore weld leg dimension is
'A(I'FAC(8<
() =en*"n? =en*"n? $!'e$$ $!'e$$ 2a3imum bending force,Fb
=
:ending stress, S, B (F,@A/)
=
Allowable welding stress for steel grade 4 ), 'w
=
'ince 'b
H
'w,therefore weld leg dimension is
'A(I'FAC(8<
6>660 kg .$, .$,5 5% % 0 !
.$$ mm $ mm 70 mm !$ mm mm .# mm 10 mm .$$ mm "
5! 0 .1 0DmmN 5."! 5."!% % 0Dmm 0DmmNN >"
LIFTING SPREADER PIPE SIING CALCULATIONS (SKID)
1)
ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
Weight of component to be lifted 4 + 'preader beam weight )
=
6>78 kg
Component force acting on beam, F
=
Impact factor
=
!
7ipe size
9
10 "n SC9 80
8uter diameter of pipe, *
=
!". mm
(hickness of pipe,
=
.%"$# mm
8uter $> @
=
'c 'c 'c"all
'ince @
H
+
'b
=
'b"all ., therefore the pipe size is
$!"$3!#'%.
$"%
LIFTING SPREADER PIPE SIING CALCULATIONS (SKID)
7)
ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
LUG SIING
F<
P
rL4s) tL4s)
d4s)
a F2
F%
hL4s)
wL4s) Lug radius, 'L($) radius, 'L($)
=
$ mm
Lug thickness, !L($)
=
7 mm
Lug base width, /L($) width, /L($)
=
.#! mm
*iameter of hole, *($) hole, *($)
=
mm
*istance from lug hole to base, L($) base, L($)
=
$ mm
Collar plate thickness, tcp
=
$ mm
Collar ring diameter, *cp
=
$ mm
Clearance btw shackle & lug size
DESIGN LOAD: 'LI0; (0'I80
7 = F8' ? (s
<(ICAL F8
Fz = 7 ? sin a
F<
=
%,%% 0
8@( 8F 7LA0 F8
F3 = 7 ? cos a
F2
=
,#$ 0
e2
=
$"$$
M%
=
!,.,%
0mm
M2
=
!.,
0mm
/orizontal dist"7I0 CL to 0"A"
)
STRESS C9 C9ECK AT =A =ASE ) M#&en! M#&en! C ! *"$!n *"$!ne e>9 In 7lane 2oment
21 = 4 F3?/ ) 4 Fz?e3 l)
8ut of plane moment
23 = 4 F1I?hL )
,) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force, 3! B F< @ !L($) !L($) H /L($)
=
.! 0
Allowable tensile stress, 't"all 4 = $"5'1 )
=
."# 0DmmN
2a3imum bending stress , 3,2 B ( 6HM2 ) @ ( /L($) H (!L($)5!)7 )
=
1 0DmmN
Allowable bending stress, fb3"all 4 = $"55'1 ) 6In 7lane
=
.5"! 0DmmN
2a3imum bending stress , 3,% B ( 6HM% ) @ !L($) 5(7H!) H /L($)7 )
=
18 0DmmN
Allowable bending stress, fb1"all 4 = $"%'1 ) 68ut 8f 7lane
=
.5".5 0DmmN
'ince ft
4
't"all, therefore the lug size is
$!"$3!#'%.
) =en*"n? =en*"n? $!'e$$ $!'e$$ (In Pne) Pne)
'ince fb3
4
fb3"all,therefore the lug size is
$!"$3!#'%.
*) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
'ince fb1
4
fb1"all,therefore the lug size is
$!"$3!#'%.
e) Un"!% Ce Ce : C#&,"ne* $!'e$$e$> @ 'ince @
=
S!@S!. 5 3,%@3,%. 5 3,2@3,2. H
., therefore the lug size is
= $!"$3!#'%.
0.76
LIFTING SPREADER PIPE SIING CALCULATIONS (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
3) S9EAR S9EAR $!'e$$ $!'e$$ (In Pne) Pne) 2a3imum '/A< stress , 3$2 B F2 @ /L($) /L($) H !L($)
=
0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
2a3imum '/A< stress , 3$% B F% @ /L($) H !L($)
=
1 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
'ince fs3
4
's"all,therefore the lug size is
$!"$3!#'%.
?) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
'ince fs3
.1) .1)
4
's"all,therefore the lug size is
$!"$3!#'%.
C9EC C9ECKI KING NG ONON-MI MISE SES S CRITE CRITERI RIA A ) 'um of stress in -7LA0
32 B S! 5 3,%
=
".$ 0DmmN
,) 'um of stress in >7LA0
3% B S! 5 3,2
=
#"$$ 0DmmN
32% B SRT (3$27)5(3$%7)
=
".. 0DmmN
F#&, B SRT (327)5(3%7)-(3253%532%7) (327)5(3%7)-(3253%532%7)
=
%5"$ 0DmmN
=
.5"! 0DmmN
2a3imum tensile force, P force, P
=
5#5$ 0
Cross sectional area of lug e1e, A! B 7 H ( !L($)H ( 'L($) - *($)@7 )) 5 7 H ( !H (( D@7) - *($)@7 )) 5 7 H ( !H (( D@7) - *( $)@7 ))
=
(ensile stress, 't
=
7.1 0DmmN
Allowable tensile stress, 't"all 4 = $"5'1 )
=
."#!5 0DmmN
) (herefore, aerage 'hear stress *) 2a3imum Combined stress Allowable combined stress 9 F comb"all 4 = $"55'1 ) 'ince fs3
)
4
's"all,therefore the lug size is
$!"$3!#'%.
STR STRESS C9ECK ECK AT PIN PIN 9OLE OLE ) Ten$"e en$"e S!'e$$ S!'e$$
'ince 't
4
't"all, therefore the lug size is
,) Se' Se' S!'e$ S!'e$$ $
!5% mmN
$!"$3!#'%.
J
2a3imum shear force, P force, P
=
Cross sectional area of lug e1e, A! B 7 H ( !L($)H ( 'L($) - *($)@7 )) 5 7 H ( !H (( D@7) - *($)@7 )) 5 7 H ( !H (( D@7) - *( $)@7 ))
=
'hear stress, 's
=
7.1 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
'ince 's
4
's"all,therefore the lug size is
$!"$3!#'%.
5#5$ 0 !5% mmN
LIFTING SPREADER PIPE SIING CALCULATIONS (SKID) ITEM :
C.I. SKID (A-6810)
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
) =e'"n? =e'"n? S!'e$$ S!'e$$ 2a3imum bearing force, P
=
Cross sectional area of lug e1e, Ab = *p ? 4 tL + !tcp )
=
!% mmN
:earing stress, 'br = Fbr D Ab
=
87.8 0DmmN
Allowable bearing stress, 'br"all 4 = $"#'1 ) 'ince 'br
4
5#5$ 0
=
'br"all,therefore the lug size is
!!"# 0DmmN
$!"$3!#'%.
*) Un"!% e> e> C#&,"ne C#&,"ne S!'e$$e$ 't
'b r
=
+
't"all
+
'br"all
(herefore, the lifting lug size is
)
's
=
0.80 "$ 4 !n 1
's"all
S!"$3!#'%.
EL ELD SI SIE E CA CALCU LCULATI LATION ONS S Weld leg used,
=
.$ mm
Weld throat thickness used, tr
=
mm
Filler metal material
9
Fillet weld Koint efficienc1,
=
$"#
Welding stress for steel grade 4 ),
=
.!% 0DmmN
Allowable welding stress,'w
=
5."!% 0DmmN
) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force,Ft
=
Area of weld, Aw = !?4tL+wL)?tr (ensile stress, 't = E4FtDAw) 'ince 't
4
'w,therefore weld leg is
5#5$ 0
=
$ mmN
=
!!" 0DmmN
$!"$3!#'%.
(,) Se' Se' $!'e$$ $!'e$$ 2a3imum shear force,Ft
=
'hear stress, 's = 4FtDAw)
=
77. 0DmmN
Allowable welding stress for steel grade 4 ) , 'w
=
5."!% 0DmmN
'ince 's
H
'w,therefore weld leg dimension is
5#5$ 0
'A(I'FAC(8<>"
() =en*"n? =en*"n? $!'e$$ $!'e$$ 2a3imum bending force,Fb
=
:ending stress, 'b = E4FbDAw)
=
.1 0DmmN
Allowable welding stress for steel grade 4 ) , 'w
=
5."!% 0DmmN
'ince 'b
H
'w,therefore weld leg dimension is
'A(I'FAC(8<>"
5! 0
SLING AND IRE ROPE CALCULATION SPREADER PIPE (SKID) ITEM : PROJECT NO.
C.I. SKID (A-6810) C.I Inje!"#n $%$!e& (A-6810) - Pe Pe'&$ F"e* S+ S+,$!'+!+'e
See!"#n #3 S"n?$ S3e #'"n? L#* (SL) *esi gn gn s af afet1 Fac to tor 0umber of leg ertical WLL
= = = =
(SLING S5 & S6) - REFER DWG
7 7 Weight of Load lifted D 0o" of legs ( Load on each sling )
= =
.,5 6.66
lb ton
(o calculate actual 'ling c apacit1 when lifting load at specified angle, a 'ling angle factor will be used as shown in the calculation below 9 TA=LE 1
'ling ratio =
#!O
ho!: USE VALUE FROM TABLE
Actua Sin! "a#acit$ "a#acit$ % Factor Rate' Rate' "a#acit$ "a#acit$ o Sin! ein! ein! u*e' 2in 0 kg !,#!! 0
LIFTING LUG *istance
=
$ mm
Lug radius, 'L
=
! mm
*iameter of hole, *
=
! mm
Lug thickness, !L
=
.! mm
Collar plate thickness, !
=
$ mm
Collar ring diameter, D
=
$ mm
Length
=
mm
Length ,
=
$ mm
7ad length, L
=
.$ mm
7ad width,
=
.$$ mm
7ad thickness, !
=
5 mm
'hell thickness, !M
=
5 mm
Angle, U
=
'hackle '"W"L
9
(1pe of shackle 7in size, D
.$ S "% tons
:8L( (1pe Anchor shackle ;!.$ =
!!"$ mm
LIFTING LUG DESIGN CALCULATION (TANK) ITEM :
T-6870 A@=
PROJ NO :
C.I Inje!"#n Inje!"#n $%$!e& $%$!e& (A-681 (A-6810) 0) - Pe'&$ Pe'&$ F"e* F"e* S+,$!'+! S+,$!'+!+'e +'e
Per PTS Section 6.3 Check a) Lug hole diameter, * shall be M2 #3
i) *p + mm
=
!%"$ mm
ii) *p - ."
%$=
!"%! mm
=
!"$ mm
b) Lug hole diameter, * shall be e$$ !n 4 (D 5 6&&) *iameter of hole, d
!
result
a) = $!"$3!#'% b) = $!"$3!#'%
/ole,d *iameter of hole, d
btw
7
!%"$
OK
!"$
Clearance btw shackle & lug size
e> C#&,"ne C#&,"ne S!'e$$e$ S!'e$$e$ S! ------------S!.
S,' 5
--------------
S$ 5
--------------
S,'.
(herefore, the lifting lug size is
S$. S!"$3!#'%.
=
0.1 "$ 4 !n 1
LIFTING LUG DESIGN CALCULATION (TANK) ITEM :
T-6870 A@=
PROJ NO :
C.I Inje!"#n Inje!"#n $%$!e& $%$!e& (A-681 (A-6810) 0) - Pe'&$ Pe'&$ F"e* F"e* S+,$!'+! S+,$!'+!+'e +'e
)
STRESS C9ECK AT SECTION A-A () =en*"n =en*"n? ? S!'e$$ S!'e$$ :ending stress due to P ( B F% 2 !n U )
=
!.# 0
:ending moment, M, ( B P 2 )
=
.%,% 0mm
'ection modulus, B ( 7H'LH!L7 @ 6 ) 5 ( 7H(DH! @ 6) )
=
!$.5 mm
:ending stress, S,n ( B M,@ )
=
".# 0D 0DmmN
'ince 'bn
$!"$3!#'%.
H
'b"all, therefore the lifting lug size is
(,) Ten$"e en$"e S!'e$$ S!'e$$ *+e !# F% Cross section area, Ae B 7'L 2 !L
=
.$$ mmN
(ensile 'tress, S! B F% @ Ae
=
.!"5 0D 0DmmN
'ince 't
$!"$3!#'%.
H
't"all, therefore the lifting lug size is
() Un"!% Un"!% e e
6)
Combine 'tress kg ,#$ 0 !
SPREADER LGTH = LENGTH SKID + 280
PIPE SIING
nasrul: INPUT -
7ipe size
9
6 "n SC9 0
8uter diameter of pipe, *
=
.5" mm
(hickness of pipe,
=
".. mm
8uter $> @
=
'c 'c 'c"all
'ince @
H
+
'b
=
'b"all ., therefore the pipe size is
$!"$3!#'%.
$"$
LIFTING SPREADER PIPE SIING CALCULATIONS (TANK)
7)
ITEM :
T-6870 A@=
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
LUG SIING
F<
P
rL4s) tL4s)
d4s)
a F2
F%
hL4s)
wL4s) Lug radius, 'L($) radius, 'L($)
=
$ mm
Lug thickness, !L($)
=
7 mm
Lug base width, /L($) width, /L($)
=
.#! mm
*iameter of hole, *($) hole, *($)
=
mm
*istance from lug hole to base, L($) base, L($)
=
$ mm
Collar plate thickness, tcp
=
$ mm
Collar ring diameter, *cp
=
$ mm
Clearance btw shackle & lug size
DESIGN LOAD: 'LI0; (0'I80
7 = F8' ? (s
<(ICAL F8
Fz = 7 ? sin a
F<
=
!.,5 0
8@( 8F 7LA0 F8
F3 = 7 ? cos a
F2
=
.!,5$ 0
e2
=
$"$$
M%
=
.,$.$,
0mm
M2
=
.$.,$#
0mm
/orizontal dist"7I0 CL to 0"A"
)
STRESS C9 C9ECK AT =A =ASE ) M#&en! M#&en! C ! *"$!n *"$!ne e>9 In 7lane 2oment
21 = 4 F3?/ ) 4 Fz?e3 l)
8ut of plane moment
23 = 4 F1I?hL )
,) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force, 3! B F< @ !L($) !L($) H /L($)
=
% 0
Allowable tensile stress, 't"all 4 = $"5'1 )
=
."# 0DmmN
2a3imum bending stress , 3,2 B ( 6HM2 ) @ ( /L($) H (!L($)5!)7 )
=
0DmmN
Allowable bending stress, fb3"all 4 = $"55'1 ) 6In 7lane
=
.5"! 0DmmN
2a3imum bending stress , 3,% B ( 6HM% ) @ !L($) 5(7H!) H /L($)7 )
=
0DmmN
Allowable bending stress, fb1"all 4 = $"%'1 ) 68ut 8f 7lane
=
.5".5 0DmmN
'ince ft
4
't"all, therefore the lug size is
$!"$3!#'%.
) =en*"n? =en*"n? $!'e$$ $!'e$$ (In Pne) Pne)
'ince fb3
4
fb3"all,therefore the lug size is
$!"$3!#'%.
*) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
'ince fb1
4
fb1"all,therefore the lug size is
$!"$3!#'%.
e) Un"!% Ce Ce : C#&,"ne* $!'e$$e$> @ 'ince @
=
S!@S!. 5 3,%@3,%. 5 3,2@3,2. H
., therefore the lug size is
= $!"$3!#'%.
0.10
LIFTING SPREADER PIPE SIING CALCULATIONS (TANK) ITEM :
T-6870 A@=
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
3) S9EAR S9EAR $!'e$$ $!'e$$ (In Pne) Pne) 2a3imum '/A< stress , 3$2 B F2 @ /L($) /L($) H !L($)
=
0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
2a3imum '/A< stress , 3$% B F% @ /L($) H !L($)
=
0 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
'ince fs3
4
's"all,therefore the lug size is
$!"$3!#'%.
?) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
'ince fs3
.1) .1)
4
's"all,therefore the lug size is
$!"$3!#'%.
C9EC C9ECKI KING NG ONON-MI MISE SES S CRITE CRITERI RIA A ) 'um of stress in -7LA0
32 B S! 5 3,%
=
.5"$! 0DmmN
,) 'um of stress in >7LA0
3% B S! 5 3,2
=
."# 0DmmN
32% B SRT (3$27)5(3$%7)
=
!"5 0DmmN
F#&, B SRT (327)5(3%7)-(3253%532%7) (327)5(3%7)-(3253%532%7)
=
!$" 0DmmN
=
.5"! 0DmmN
2a3imum tensile force, P force, P
=
!%!5$ 0
Cross sectional area of lug e1e, A! B 7 H ( !L($)H ( 'L($) - *($)@7 )) 5 7 H ( !H (( D@7) - *($)@7 )) 5 7 H ( !H (( D@7) - *( $)@7 ))
=
(ensile stress, 't
=
. 0DmmN
Allowable tensile stress, 't"all 4 = $"5'1 )
=
."#!5 0DmmN
) (herefore, aerage 'hear stress *) 2a3imum Combined stress Allowable combined stress 9 F comb"all 4 = $"55'1 ) 'ince fs3
)
4
's"all,therefore the lug size is
$!"$3!#'%.
STR STRESS C9ECK ECK AT PIN PIN 9OLE OLE ) Ten$"e en$"e S!'e$$ S!'e$$
'ince 't
4
't"all, therefore the lug size is
,) Se' Se' S!'e$ S!'e$$ $
!5% mmN
$!"$3!#'%.
J
2a3imum shear force, P force, P
=
Cross sectional area of lug e1e, A! B 7 H ( !L($)H ( 'L($) - *($)@7 )) 5 7 H ( !H (( D@7) - *($)@7 )) 5 7 H ( !H (( D@7) - *( $)@7 ))
=
'hear stress, 's
=
. 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
'ince 's
4
's"all,therefore the lug size is
$!"$3!#'%.
!%!5$ 0 !5% mmN
LIFTING SPREADER PIPE SIING CALCULATIONS (TANK) ITEM :
T-6870 A@=
PROJE PROJECT CT NO. NO.
C.I C.I Inje Inje! !"# "#n n $%$!e $%$!e& & (A-6 (A-681 810) 0) - Pe' Pe'& &$ $ F"e F"e* * S+,$! S+,$!'+ '+! !+' +'e e
) =e'"n? =e'"n? S!'e$$ S!'e$$ 2a3imum bearing force, P
=
Cross sectional area of lug e1e, Ab = *p ? 4 tL + !tcp )
=
!% mmN
:earing stress, 'br = Fbr D Ab
=
0.67 0DmmN
Allowable bearing stress, 'br"all 4 = $"#'1 ) 'ince 'br
4
!%!5$ 0
=
'br"all,therefore the lug size is
!!"# 0DmmN
$!"$3!#'%.
*) Un"!% e> e> C#&,"ne C#&,"ne S!'e$$e$ 't
'b r
=
+
't"all
+
'br"all
(herefore, the lifting lug size is
)
's
=
0.0 "$ 4 !n 1
's"all
S!"$3!#'%.
EL ELD SI SIE E CA CALCU LCULATI LATION ONS S Weld leg used,
=
.$ mm
Weld throat thickness used, tr
=
mm
Filler metal material
9
Fillet weld Koint efficienc1,
=
$"#
Welding stress for steel grade 4 ),
=
.!% 0DmmN
Allowable welding stress,'w
=
5."!% 0DmmN
) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force,Ft
=
Area of weld, Aw = !?4tL+wL)?tr
=
(ensile stress, 't = E4FtDAw) 'ince 't
4
= 'w,therefore weld leg is
!%!5$ 0 $ mmN ". 0DmmN
$!"$3!#'%.
(,) Se' Se' $!'e$$ $!'e$$ 2a3imum shear force,Ft
=
'hear stress, 's = 4FtDAw)
=
8.1 0DmmN
Allowable welding stress for steel grade 4 ) , 'w
=
5."!% 0DmmN
'ince 's
H
'w,therefore weld leg dimension is
!%!5$ 0
'A(I'FAC(8<>"
() =en*"n? =en*"n? $!'e$$ $!'e$$ 2a3imum bending force,Fb
=
:ending stress, 'b = E4FbDAw)
=
.1 0DmmN
Allowable welding stress for steel grade 4 ) , 'w
=
5."!% 0DmmN
'ince 'b
H
'w,therefore weld leg dimension is
'A(I'FAC(8<>"
5! 0
SLING AND IRE ROPE CALCULATION SPREADER PIPE (TANK ) ITEM : PROJECT NO.
T-6870 A@= C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
See!"#n #3 S"n?$ S3e #'"n? L#* (SL) *es ig ign safet1 Fac to tor 0umber of leg ertical WLL
= = = =
(SLING S5 & S6) - REFER DWG
1 7 Weight of Load lifted D 0o" of legs ( Load on each sling )
= =
,$%# 1.8
lb ton
(o calculate actual 'ling capacit1 when li fting load at specified angle, a 'ling angle factor will be used as shown in the calculation below 9 TA=LE 1
'ling ratio =
.5O
Actua Sin! "a#acit$ "a#acit$ % Factor Rate' Rate' "a#acit$ "a#acit$ o Sin! ein! ein! u*e' 2in USED OT9ER ROPE SL (A*"$,e +$"n? ,e#/ 80 : eQQ
"'e R#e D"&e!e' +!"#n Sae or0in! oa' % ('ia+eter)1 2 /
Wire rope diameter (inch) & SWL ( tonne )
(he aboe formula can be used to e*ti+ate 'WL of the wire rope to be used when lifting the l oads" (herefore, the estimated estimated diameter of wire ropes ropes is 9 Wire ro#e 'ia+eter 'ia+eter % S,RT (SWL o ire ro#e /) % $" $"$. $. in % 11.180 mm (o @sed Q
17
mm
(See n#!e)
NTE 4 ( E*ti+ate' aue* on$. Pea*e con*ut ire ro#e +anuacturer or conir+ation on rate' SWL o ire ro#e cacuate')
SUMMAR; WI< <87 *IA2(< @'* 'WL 8F 'LI0; @'* 2I0" <R@I<* 'WL 8F 'LI0;
= = =
17 mm 1. ton 1.8 ton
(See n#!e)
SLING AND IRE ROPE CALCULATION (TANK ) LIFTING LUG ITEM : PROJECT NO.
T-6870 A@= C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
See!"#n #3 S"n?$ S3e #'"n? L#* (SL) *es ig ign safet1 Fac to tor 0umber of leg ertical WLL
= = = =
(SLING S S1 S3 S7 ) - REFER DWG
7 Weight of Load lifted D 0o" of legs ( Load on each sling )
= =
!,.$$ 0.
lb ton
(o calculate actual 'ling capacit1 when li fting load at specified angle, a 'ling angle factor will be used as shown in the calculation below 9 TA=LE 1
'ling ratio =
Actua Sin! "a#acit$ "a#acit$ % Factor Rate' Rate' "a#acit$ "a#acit$ o Sin! ein! ein! u*e' 2in USED OT9ER ROPE SL (A*"$,e +$"n? ,e#/ 80 : eQQ
"'e R#e D"&e!e' +!"#n Sae or0in! oa' % ('ia+eter)1 2 /
Wire rope diameter (inch) & SWL ( tonne )
(he aboe formula can be used to e*ti+ate 'WL of the wire rope to be used when lifting the l oads" (herefore, the estimated estimated diameter of wire ropes ropes is 9 Wire ro#e 'ia+eter 'ia+eter % S,RT (SWL o ire ro#e /) % $"5 $"5!! !! in % .70707 mm (o @sed Q
10
mm
(See n#!e)
NTE 4 ( E*ti+ate' aue* on$. Pea*e con*ut ire ro#e +anuacturer or conir+ation on rate' SWL o ire ro#e cacuate')
SUMMAR; WI< <87 *IA2(< @'* 'WL 8F 'LI0; @'* 2I0" <R@I<* 'WL 8F 'LI0;
= = =
10 mm 1.0 ton 0. ton
(See n#!e)
LIFTING LUG DESIGN CALCULATION (TANK) ITEM :
T-771
PROJ NO :
C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
ARNING : DO NOT LIFT MORE LIFT MORE T9AN 10.00
Fy
°
J@
OF ANGLE U
Dcp
w2
tL rL
d
A
nasrul: PLEASE MACRO
w2
A
tcp
k
tank b
Pad plate
Wp
w3 tp
a w1
tM
Lp
Weight of skid , We 0umber of lifting lug, 0
1)
=
0 kg
=
$ 0
=
LIFTING LUG *istance
=
$ mm
Lug radius, 'L
=
! mm
*iameter of hole, *
=
! mm
Lug thickness, !L
=
.! mm
Collar plate thickness, !
=
$ mm
Collar ring diameter, D
=
$ mm
Length
=
mm
Length ,
=
$ mm
7ad length, L
=
.$ mm
7ad width,
=
.$$ mm
7ad thickness, !
=
5 mm
'hell thickness, !M
=
5 mm
Angle, U
=
'hackle '"W"L
9
(1pe of shackle 7in size, D
.$ S "% tons
:8L( (1pe Anchor shackle ;!.$ =
!!"$ mm
LIFTING LUG DESIGN CALCULATION (TANK) ITEM :
T-771
PROJ NO :
C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
Per PTS Section 6.3 Check a) Lug hole diameter, * shall be M2 #3
i) *p + mm
=
!%"$ mm
ii) *p - ."
%$=
!"%! mm
=
!"$ mm
b) Lug hole diameter, * shall be e$$ !n 4 (D 5 6&&) *iameter of hole, d
!
result
a) = $!"$3!#'% b) = $!"$3!#'%
/ole,d *iameter of hole, d
btw
7
!%"$
OK
!"$
Clearance btw shackle & lug size
e> C#&,"ne C#&,"ne S!'e$$e$ S!'e$$e$ S! ------------S!.
S,' 5
--------------
S$ 5
--------------
S,'.
(herefore, the lifting lug size is
S$. S!"$3!#'%.
=
0.00 "$ 4 !n 1
LIFTING LUG DESIGN CALCULATION (TANK) ITEM :
T-771
PROJ NO :
C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
)
STRESS C9ECK AT SECTION A-A () =en =en*"n *"n? ? S!'e$$ S!'e$$ :ending stress due to P ( B F% 2 !n U )
=
$ 0
:ending moment, M, ( B P 2 )
=
$ 0mm
'ection modulus, B ( 7H'LH!L7 @ 6 ) 5 ( 7H(DH! @ 6) )
=
!$.5 mm
:ending stress, S,n ( B M,@ )
=
$"$$ 0DmmN
'ince 'bn
$!"$3!#'%.
H
'b"all, therefore the lifting lug size is
(,) Ten$" en$"e e S!'e$$ S!'e$$ *+e !# F% Cross section area, Ae B 7'L 2 !L
=
.$$ mmN
(ensile 'tress, S! B F% @ Ae
=
$"$$ 0DmmN
'ince 't
$!"$3!#'%.
H
't"all, therefore the lifting lug size is
() Un" Un"!% !% e e
6)
Combine 'tress $> @
=
'c 'c 'c"all
'ince @
H
+
'b
=
'b"all ., therefore the pipe size is
$!"$3!#'%.
$"$.
LIFTING SPREADER PIPE SIING CALCULATIONS (TANK)
7)
ITEM :
T-771
PROJECT NO.
C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
LUG SIING
F<
P
rL4s) tL4s)
d4s)
a F2
F%
hL4s)
wL4s) Lug radius, 'L($) radius, 'L($)
=
$ mm
Lug thickness, !L($)
=
7 mm
Lug base width, /L($) width, /L($)
=
.#! mm
*iameter of hole, *($) hole, *($)
=
mm
*istance from lug hole to base, L($) base, L($)
=
$ mm
Collar plate thickness, tcp
=
$ mm
Collar ring diameter, *cp
=
$ mm
Clearance btw shackle & lug size
DESIGN LOAD: 'LI0; (0'I80
7 = F8' ? (s
<(ICAL F8
Fz = 7 ? sin a
F<
=
!# 0
8@( 8F 7LA0 F8
F3 = 7 ? cos a
F2
=
.5 0
e2
=
$"$$
M%
=
.,%.
0mm
M2
=
.,%
0mm
/orizontal dist"7I0 CL to 0"A"
)
STRESS C9 C9ECK AT =A =ASE ) M#&en! M#&en! C ! *"$!n *"$!ne e>9 In 7lane 2oment
21 = 4 F3?/ ) 4 Fz?e3 l)
8ut of plane moment
23 = 4 F1I?hL )
,) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force, 3! B F< @ !L($) !L($) H /L($)
=
$ 0
Allowable tensile stress, 't"all 4 = $"5'1 )
=
."# 0DmmN
2a3imum bending stress , 3,2 B ( 6HM2 ) @ ( /L($) H (!L($)5!)7 )
=
0 0DmmN
Allowable bending stress, fb3"all 4 = $"55'1 ) 6In 7lane
=
.5"! 0DmmN
2a3imum bending stress , 3,% B ( 6HM% ) @ !L($) 5(7H!) H /L($)7 )
=
0 0DmmN
Allowable bending stress, fb1"all 4 = $"%'1 ) 68ut 8f 7lane
=
.5".5 0DmmN
'ince ft
4
't"all, therefore the lug size is
$!"$3!#'%.
) =en*"n? =en*"n? $!'e$$ $!'e$$ (In Pne) Pne)
'ince fb3
4
fb3"all,therefore the lug size is
$!"$3!#'%.
*) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
'ince fb1
4
fb1"all,therefore the lug size is
$!"$3!#'%.
e) Un"!% Ce Ce : C#&,"ne* $!'e$$e$> @ 'ince @
=
S!@S!. 5 3,%@3,%. 5 3,2@3,2. H
., therefore the lug size is
= $!"$3!#'%.
0.00
LIFTING SPREADER PIPE SIING CALCULATIONS (TANK) ITEM :
T-771
PROJECT NO.
C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
3) S9EAR S9EAR $!'e$$ $!'e$$ (In Pne) Pne) 2a3imum '/A< stress , 3$2 B F2 @ /L($) /L($) H !L($)
=
0 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
2a3imum '/A< stress , 3$% B F% @ /L($) H !L($)
=
0 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
'ince fs3
4
's"all,therefore the lug size is
$!"$3!#'%.
?) =en*"n? =en*"n? $!'e$$ $!'e$$ (O+! #3 Pne) Pne)
'ince fs3
.1) . 1)
4
's"all,therefore the lug size is
$!"$3!#'%.
C9EC C9 ECKI KING NG ONON-MI MISE SES S CRITE CRITERI RIA A ) 'um of stress in -7LA0
32 B S! 5 3,%
=
$"!. 0DmmN
,) 'um of stress in >7LA0
3% B S! 5 3,2
=
$".# 0DmmN
32% B SRT (3$27)5(3$%7)
=
$"$ 0DmmN
F#&, B SRT (327)5(3%7)-(3253%532%7) (327)5(3%7)-(3253%532%7)
=
rr9%$! 0DmmN
=
.5"! 0DmmN
) (herefore, aerage 'hear stress *) 2a3imum Combined stress Allowable combined stress 9 F comb"all 4 = $"55'1 ) 'ince fs3
)
4
's"all,therefore the lug size is
E'':07
STR ST RESS C9EC ECK K AT PIN PIN 9OL OLE E ) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force, P force, P
=
Cross sectional area of lug e1e, A! B 7 H ( !L($)H ( 'L($) - *($)@7 )) 5 7 H ( !H (( D@7) - *($)@7 )) 5 7 H ( !H (( D@7) - *( $)@7 ))
=
(ensile stress, 't
=
0.17 0DmmN
Allowable tensile stress, 't"all 4 = $"5'1 )
=
."#!5 0DmmN
2a3imum shear force, P force, P
=
0
Cross sectional area of lug e1e, A! B 7 H ( !L($)H ( 'L($) - *($)@7 )) 5 7 H ( !H (( D@7) - *($)@7 )) 5 7 H ( !H (( D@7) - *( $)@7 ))
=
'hear stress, 's
=
0.17 0DmmN
Allowable shear stress, 's"all 4 = $"'1 )
=
##"! 0DmmN
'ince 't
4
't"all, therefore the lug size is
,) Se' Se' S!'e$ S!'e$$ $
'ince 's
0 !5% mmN
$!"$3!#'%.
J
4
's"all,therefore the lug size is
$!"$3!#'%.
!5% mmN
LIFTING SPREADER PIPE SIING CALCULATIONS (TANK) ITEM :
T-771
PROJECT NO.
C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
) =e'"n? =e'"n? S!'e$$ S!'e$$ 2a3imum bearing force, P
=
0
Cross sectional area of lug e1e, Ab = *p ? 4 tL + !tcp )
=
!% mmN
:earing stress, 'br = Fbr D Ab
=
0.0 0DmmN
Allowable bearing stress, 'br"all 4 = $"#'1 ) 'ince 'br
4
=
'br"all,therefore the lug size is
!!"# 0DmmN
$!"$3!#'%.
*) Un"!% e> e> C#&,"ne C#&,"ne S!'e$$e$ 't
'b r
=
+
't"all
+
'br"all
(herefore, the lifting lug size is
)
's
=
0.00 "$ 4 !n 1
's"all
S!"$3!#'%.
EL E LD SI SIE E CA CALC LCU ULA LATI TION ONS S Weld leg used,
=
.$ mm
Weld throat thickness used, tr
=
mm
Filler metal material
9
Fillet weld Koint efficienc1,
=
$"#
Welding stress for steel grade 4 ),
=
.!% 0DmmN
Allowable welding stress,'w
=
5."!% 0DmmN
) Ten$"e en$"e S!'e$$ S!'e$$ 2a3imum tensile force,Ft
=
Area of weld, Aw = !?4tL+wL)?tr
=
(ensile stress, 't = E4FtDAw)
0 $ mmN
=
$".. 0DmmN
2a3imum shear force,Ft
=
0
'hear stress, 's = 4FtDAw)
=
0.11 0DmmN
Allowable welding stress for steel grade 4 ) , 'w
=
5."!% 0DmmN
'ince 't
4
'w,therefore weld leg is
$!"$3!#'%.
(,) Se' Se' $!'e$$ $!'e$$
'ince 's
H
'w,therefore weld leg dimension is
'A(I'FAC(8<>"
() =en*"n? =en*"n? $!'e$$ $!'e$$ 2a3imum bending force,Fb
=
:ending stress, 'b = E4FbDAw)
=
.1 0DmmN
Allowable welding stress for steel grade 4 ) , 'w
=
5."!% 0DmmN
'ince 'b
H
'w,therefore weld leg dimension is
'A(I'FAC(8<>"
5! 0
SLING AND IRE ROPE CALCULATION SPREADER PIPE (TANK ) ITEM : PROJECT NO.
T-771 C.I Inje!"#n $%$!e& (A-6810) - Pe'&$ F"e* S+,$!'+!+'e
See!"#n #3 S"n?$ S3e #'"n? L#* (SL) *esi gn gn safet1 Factor 0umber of leg ertical WLL
= = = =
(SLING S5 & S6) - REFER DWG
7 7 Weight of Load lifted D 0o" of legs ( Load on each sling )
= =
$ 0.00
lb ton
(o calculate actual 'ling capacit1 when li fting load at specified angle, a 'ling angle factor will be used as shown in the calculation below 9 TA=LE 1
'ling ratio =
$O
ho!: USE VALUE FROM TABLE
Actua Sin! "a#acit$ "a#acit$ % Factor Rate' Rate' "a#acit$ "a#acit$ o o Sin! ein! u*e' u*e' 2i n 000 mm
Cross sectional area, A
=
5,.5 mmN
'ection modulus , B33
=
%,#$%,5$$ mmT
2aterial used
=
A 5
'pecified 1ield stress, '1
=
!"!. 0DmmN
) =en*"n =en*"n? ? S!'e$$ S!'e$$ F3
<.
L e> C#&,"ne C#&,"ne S!'e$$e$ S!'e$$e$ 't 't"all
'b r +
'br"all
(herefore, the lifting lug size is
's +
's"all
S!"$3!#'%.
=
0.00 "$ 4 !n 1
LIFTING LUG DESIGN CALCULATION (SKID) ITEM : PROJECT NO.
T-601 SKO P"e"ne$ F""!"e$ Rej+en!"#n P'#je! : LK-A
.0 STRESS C9ECK C9ECK AT AT SECTION A-A A-A () =en*"n =en*"n? ? S!'e$$ S!'e$$ :ending stress due to 7a 4 = F1 3 tan @ ) :ending moment, 2b 4 = 7a 3 k )
= =
!% 0 .,## 0mm
'ection modulus, B 4 = 4!?rL?tL !D5) + 4!?4*cp?tcpD5))
=
.!55 mm
:ending stress, 'bn 4 = 2bDB )
=
'ince 'bn
$!"$3!#'%.
H
'b"all, therefore the lifting lug size is
$".5 0DmmN
(,) Ten$"e Ten$"e S!'e$$ S!'e$$ *+e *+e !# F% Cross section area, Ae 4=!rL 3 tL)
=
(ensile 'tress, 't 4=F1DAe)
=
'ince 't
H
't"all, therefore the lifting lug size is
!$$ mmN $"$% 0DmmN
$!"$3!#'%.
() Un"!% Un"!% e e Combine 'tress
